A box is placed on the floor of a truck moving with an acceleration of 7 ms–2. If the coefficient of kinetic friction between the box and surface of the truck is 0.5, find the acceleration of the box relative to the truck

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1.7ms-2

2.1ms-2

3.5ms-2

4.5ms-2

answer is B.

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Detailed Solution

ab = aT - µg= 7 – 0.5 × 9.8ab = 7 – 4.9ab = 2.1 m/s2

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