Questions
A boy of mass 25kg slides down a rope hanging from the branch of a tree. If the force of friction against him is 50N, the boy’s acceleration is (g=10ms–2)
detailed solution
Correct option is C
Net downward force acting on the boy = mg - fk ⇒ (25 x 10 - 50)N = 200N Acceleration =Talk to our academic expert!
Similar Questions
A skier starts from rest at point A and slides down the hill without turning or breaking. The friction coefficient is . When he stops at point B, his horizontal displacement is s. What is the height difference between points A and B?
(The velocity of the skier is small, so that the additional pressure on the snow due to the curvature
can be neglected. Neglect also the friction of air and the dependence of on the velocity of the skier.)
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