A boy of mass $$4$$ kg is standing on a piece of wood having mass $$5$$ kg. If the coefficient of friction between the wood and the floor is $$0.5$$, the maximum force that the boy can exert on the rope so that the piece of wood does not move from its place is $$______$$ N. (Round$$ off to the Nearest $$integer)(Take$$ $$g=10ms$$−$$2)

Question

A boy of mass $$4$$ kg is standing on a piece of wood having mass $$5$$ kg. If the coefficient of friction between the wood and the floor is $$0.5$$, the maximum force that the boy can exert on the rope so that the piece of wood does not move from its place is $$______$$ N. (Round$$ off to the Nearest $$integer)(Take$$  $$g=10ms$$−$$2)

Infinity Learn · Accepted Answer

FBD for wood,Horizontal , $$T=fL=$$μNVertical, $$N=N1+mg$$⇒$$T=$$μ$$N1+mg$$........(1)FBD$$ for manVertical, $$N1=m1g$$−T .........$$(2)   put (2) in (1) ⇒$$T=$$μ$$m1g$$−T $$+mg$$ ⇒$$T=$$μ$$m1g+mg1+$$μ$$=0.5$$×$$901.5=30N$$

Friction

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Friction

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FBD for wood,Horizontal , T=fL=μNVertical, N=N1+mg⇒T=μN1+mg........(1)FBD for manVertical, N1=m1g−T .........(2) put (2) in (1) ⇒T=μm1g−T +mg ⇒T=μm1g+mg1+μ=0.5×901.5=30N

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