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A boy of mass m is sliding down a vertical pole by pressing it with a horizontal force f. If μ is the coefficient of friction between his palms and the pole, the acceleration with which he slides down will be


Normal reaction R = f. 

Therefore, force of friction =μR=μf

The net downward force F=mgμf

Hence, the acceleration a=Fm=mgμfm=gμfm

Hence the correct choice is (d).

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