Q.

A boy of mass m is sliding down a vertical pole by pressing it with a horizontal force f. If μ is the coefficient of friction between his palms and the pole, the acceleration with which he slides down will be

Moderate

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a

g

b

μfm

c

g+μfm

d

g−μfm

answer is 4.

(Detailed Solution Below)

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Detailed Solution

Normal reaction R = f. Therefore, force of friction =μR=μf. The net downward force F=mg−μf. Hence, the acceleration a=Fm=mg−μfm=g−μfm. Hence the correct choice is (d).
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