A boy of mass m is sliding down a vertical pole by pressing it with a horizontal force f. If μ is the coefficient of friction between his palms and the pole, the acceleration with which he slides down will be

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μfm

g+μfm

g−μfm

answer is D.

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Detailed Solution

Normal reaction R = f. Therefore, force of friction =μR=μf. The net downward force F=mg−μf. Hence, the acceleration a=Fm=mg−μfm=g−μfm. Hence the correct choice is (d).

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