Questions
A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle of 30o with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground?
detailed solution
Correct option is A
We know thatR=u2sin2θg=(10)2×sin60∘10=10×(3/2)=53=8⋅66mTalk to our academic expert!
Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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