First slide

Projectile motion

Question

A boy projects a stone vertically perpendicular to the trolley car with a speed v. If the trolley car moves with a constant velocity u, the time of flight of the stone is:

Moderate

A

$\frac{u + v}{g}$
B

$\frac{2 v}{g}$
C

$\frac{2 u}{g}$
D

none of these

Solution

$\begin{array}{l} v_{0} \sin θ = v . . . . . . (i) \\ v_{0} \cos θ = u . . . . . (i i) \end{array}$
Time of flight depends on vertical component of velocity.
$T = \frac{2 v_{0} \sin θ}{g} = \frac{2 v}{g}$

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