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Q.

A boy projects a stone vertically perpendicular to the trolley car with a speed v. If the trolley car moves with a constant velocity u, the time of flight of the stone is:

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a

u+vg

b

2vg

c

2ug

d

none of these

answer is B.

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Detailed Solution

v0sin⁡θ=v ......(i)v0cos⁡θ=u .....(ii) Time of flight depends on vertical component of velocity.T=2v0sin⁡θg=2vg

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A boy projects a stone vertically perpendicular to the trolley car with a speed v. If the trolley car moves with a constant velocity u, the time of flight of the stone is: