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Q.

A boy is swinging on a swing such that his lowest and highest positions are at heights of 2m and 4.5m respectively. His velocity at the lowest position is,

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a

2.5ms−1

b

7ms−1

c

14ms−1

d

20 ms−1

answer is B.

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Detailed Solution

12mV2=mg(h2−h1) ⇒V=2g(h2−h1) =2×9.8(4.5−2)=7m/s

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