First slide

Vertical projection from ground

Question

A boy throws n balls per second at regular time intervals. When the first ball reaches the maximum height he throws the second one vertically up. The maximum height reached by each ball is

Moderate

A

$\frac{g}{2 n^{2} - 1}$
B

$\frac{g}{2 n^{2}}$
C

$\frac{g}{n^{2}}$
D

$\frac{g}{n}$

Solution

Time taken by a ball to reach the maximum height i.e., time of ascent $(t_{a})$ of each ball is 1/n sec
$t_{a}$ = u/g = 1/n ⇒ u = g/n
$H_{m a x}$ = $\frac{u^{2}}{2 g}$ = ${(\frac{g}{n})}^{2} \frac{1}{2 g}$ = $\frac{g}{2 n^{2}}$

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