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Q.

A boy throws n balls per second at regular time intervals. When the first ball reaches the maximum height he throws the second one vertically up. The maximum height reached by each ball is

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a

g2n2-1

b

g2n2

c

gn2

d

gn

answer is B.

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Detailed Solution

Time taken by a ball to reach the maximum height i.e., time of ascent ta of each ball is 1/n secta = u/g = 1/n ⇒ u = g/nHmax =u22g= gn212g =g2n2
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