A boy walks to his school at a distance of 6 km with constant speed of 2.5 km/h and walks back with a constant speed of 4 km/h. His average speed for the round trip is

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5 km h−1

4013 km h−1

3 km/h

12 km h−1

answer is B.

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Detailed Solution

Average speed for equal distance = 2v1v2v1+v2

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