Download the app

Questions  

A brass cube of side a and density σ is floating in mercury of density ρ. If the cube is displaced a bit vertically, it executes S.H.M. Its time period will be

a
2πσaρg
b
2πρaσg
c
2πρgσa
d
2πσgρa

detailed solution

Correct option is

As a is the side of cube σ is its density.Mass of cube is a2 σ its weight = a3σgLet h be the height of cube immersed in liquid of density ρ in equilibrium then, F = a2hρg = Mg = a3σgIf it is pushed down by y then the buoyant forceF' = a2(h+y)ρgRestoring force is ∆F = F'-F = a2(h+y)σg-a2hσg                           = a2yρgRestoring acceleration = ∆FM = -a2yρgM = -a2ρga2σyMotion is S.H.M.⇒T =2πa3σa2ρg = 2πaσρg

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

 

The system shown in figure is in equilibrium. The mass of the container with liquid is M, density of liquid in the container is ρ and the volume of the block is V. If the container is now displaced downwards through a distance x0 and released such that the block remains well inside the liquid, then during subsequent motion, 


phone icon
whats app icon