Q.
A brass wire 1.8 m long at 27°C is held taut with little tension between the two rigid supports. If the wire is cooled to a temperature of -39°C , the tension developed in the wire, if its diameter is 2.0 mm, Coefficient of linear expansion of brass = 2.0×10-5K-1 ; Young’s modulus of brass = 0.91×1011Pa
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a
3.8×102 N
b
5.8×102 N
c
7.8×102 N
d
6.8×102 N
answer is A.
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Detailed Solution
Decrease in length due to tensionΔl=FlAY ...(1)Increase in length due to rise in temperatureΔ=laΔt ...(2) from (1) and (2) FlAY=lαΔt⇒F=YAαΔT
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