First slide

Elastic behaviour of solids

Question

The breaking stress for a substance is 10⁶ N/ m² . what length of the wire of this substance should be suspended vertically so that the wire breaks under its own weight? (Given : density of material of the wire = 4 x 10³ kg/m³ and g = 10 ms^-2)

Moderate

A

10 m
B

15 m
C

25 m
D

34 m

Solution

$Breaking stress = \frac{Maximum weight}{Area of cross section}$
$\begin{array}{l} 10^{6} = \frac{alρg}{a} = lρg \\ or l = \frac{10^{6}}{ρg} = \frac{10^{6}}{4 \times 10^{3} \times 10} m = 25 m \end{array}$

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