A bucket of mass ‘m’ tied to a light rope is lowered at a constant acceleration of ‘g/4’. If the bucket is lowered by a distance ‘d’, the work done by the rope will be (neglect the mass of the rope)

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m g d/4

3mgd/4

-3mgd/4

-5mgd/4

answer is C.

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Detailed Solution

W = F S COS 1800= -M(g-g4)d=-3mgd4

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