First slide

Work done by Diff type of forces

Question

A bucket of mass ‘m’ tied to a light rope is lowered at a constant acceleration of ‘g/4’. If the bucket is lowered by a distance ‘d’, the work done by the rope will be (neglect the mass of the rope)

Easy

A

m g d/4
B

3mgd/4
C

-3mgd/4
D

-5mgd/4

Solution

W = F S COS $180^{0}$ = -M(g- $\frac{g}{4}$ )d= $\frac{- 3 m g d}{4}$

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