Bulb $$B1$$ has rating $$P1$$ watt, V volt and bulb $$B2$$ has rating $$P2$$ watt, V volt. If $$P1$$ > $$P2$$, then

Resistances of $$B1$$ and $$B2$$ are given by $$R1$$ $$=$$ $$V2/P1$$ and $$R2$$ $$=$$ $$V2/P2$$ respectively.In $$combination-I$$, $$P11=Vo2R1$$ and $$P21=$$ $$V02R2$$. since $$R1$$ $$P21$$ .In $$combination-II$$, $$P11=i2R1$$ and $$P21=i2R2$$ . since $$R1$$ < $$R2$$, we can conclude $$P11$$

Questions

Bulb B₁ has rating P₁ watt, V volt and bulb B₂has rating P₂ watt, V volt. If P₁ > P₂, then

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In combination-I, brightness of B1 is less than the brightness of B2.

In combination -II brightness of B1 is more than the brightness of B2.

In combination-I brightness of B1 is same as the brightness of B2.

In combination-II, brightness of B1 is less than the brightness of B2.

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detailed solution

Correct option is D

Resistances of B1 and B2 are given by R1 = V2/P1 and R2 = V2/P2 respectively.In combination-I, P11=Vo2R1 and P21= V02R2. since R1 < R2, we can conclude P11>P21 .In combination-II, P11=i2R1 and P21=i2R2 . since R1 < R2, we can conclude P11

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