A bulb is rated at 100V, 100W, it can be treated as a resistor. Find out the inductance of an inductor (called choke coil) that should be connected in series with the bulb to operate the bulb at its rated power with the help of an ac source of 200V and 50 Hz.

From the rating of the bulb, the resistance of the bulb can be calculated.R=Vrms2P=100ΩFor the bulb to be operated at its rated value the rms current through it should be P=VI   100=100I   and  I=1now as the input voltage is 200 =iR2+XL2  putting R=100 we get  XL=1003Lω=1003 L=1003100π=3π