The bulk modulus of rubber is 9 x 108 N/m2. To what depth below the surface of sea should the rubber ball be taken as to decrease its volume by 0.1%?

ΔP=BVV Here VV=0⋅1100∴ΔP=9×105Atmospheric pressure at sea level =10 m of water column.Let the ball is taken to a depth h. ThenΔP=(h−10)ρg9×105=(h−10)(1000)∴ h=100m