A bullet is fired from a gun. The force on the bullet is given by F = 600−2×105t  Where, F is in newton and t in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. The average impulse imparted to the bullet  is …….

Given F=600−2×105t The force is zero at time t, given by0=600−2×105t ⇒t=6002×105=3×10−3 seconds∴  Impulse = ∫0tFdt=∫03×10−3(600−2×105t)dt                   =[600t−2×105t22]3×10−3                   =600×3×10−3−105(3×10−3)2                   =1.8−0.9=0.9Ns