A bullet is fired from a gun. The force on the bullet is given by F = 600 – (2 × 105t), where F is in newton and 't' is in second. The force on the bullet becomes zero as soon as it leaves the barrel. The average impulse imparted to the bullet is

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answer is 3.

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Detailed Solution

F = 600 – (2 × 105t) = 0600 = 2 × 105t Impulse I =

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