A bullet fired into a fixed target loses half of its velocity after penetrating through a distance 1 cm. How much further distance it will penetrate before coming to rest. (Assuming that it faces constant retardation)
v 2 -u 2 =2 a s
for 1cm distance
(u/2) 2 -u 2 =2 a s
-3u 2 /4=2 a
a= -3u 2 /8
0-u 2=2(-3u 2/8) s 1
s 1 =4/3
further distance is 4/3-1 =