A bullet of mass $$20$$ g moving with $$600$$ $$ms-1$$ collides with a block of mass $$4$$ kg hanging with the string of length $$0.4$$ m. What is velocity of bullet when it comes out of block, if block rises to height $$0.2$$ m after collision? (Take$$, g $$=$$ $$10$$ $$ms-2)

Question

A bullet of mass $$20$$ g moving with $$600$$ $$ms-1$$ collides with a block of mass $$4$$ kg hanging with the string of length $$0.4$$ m. What is velocity of bullet when it comes out of block, if block rises to height $$0.2$$ m after collision? (Take$$, g $$=$$ $$10$$ $$ms-2)

Infinity Learn · Accepted Answer

Velocity of block just after collision $$=2gh=2$$×$$10$$×$$0.2$$                                                        $$=2$$ $$ms-1Now$$, applying conservation of linear momentum just before and just after collision,                         $$0.02$$ × $$600$$ $$=$$ $$4$$ × $$2$$ $$+$$ $$0.02$$ × v∴                                     v $$=$$ $$200$$ $$ms-1$$

A bullet of mass 20 g moving with $600 {ms}^{- 1}$ collides with a block of mass 4 kg hanging with the string of length 0.4 m. What is velocity of bullet when it comes out of block, if block rises to height 0.2 m after collision? (Take, $g = 10 {ms}^{- 2}$ )

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A bullet of mass 20 g moving with 600 ms-1 collides with a block of mass 4 kg hanging with the string of length 0.4 m. What is velocity of bullet when it comes out of block, if block rises to height 0.2 m after collision? (Take, g = 10 ms-2)

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A bullet of mass 20 g moving with $600 {ms}^{- 1}$ collides with a block of mass 4 kg hanging with the string of length 0.4 m. What is velocity of bullet when it comes out of block, if block rises to height 0.2 m after collision? (Take, $g = 10 {ms}^{- 2}$ )