Q.

A bullet of mass 5g , Travelling with a speed of  210 m/s , strikes a fixed wooden target . One half its kinetic energy is converted in to heat in the bullet while the other half is converted in to heat in the wood. The rise of temperature of the bullet if the specific heat of the material is 0.030 cal/g-0C1cal=4.2×107ergs close to:

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a

87.50C

b

119.20C

c

83.30C

d

38.40C

answer is 1.

(Detailed Solution Below)

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Detailed Solution

One half of kinetic energy is used up in heating the bullet.​∴1212mv2 = msΔT ​⇒14 210002 =0.03×4.2×1071×ΔT​⇒ΔT=441×1064×0.03×4.2×107=87.50C
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