First slide

Second law

Question

A bullet of mass 10^-3kg strikes an obstacle and moves at 60° to its original direction. If its speed also changes from 20 m/s to 10 m/s , the magnitude of the impulse acting on the bullet is

Moderate

A

$10^{- 2} N - s$
B

$5 \sqrt{3} \times 10^{- 3} N - s$
C

$15 \times 10^{- 3} N - S$
D

$\sqrt{3} \times 10^{- 2} N - s$

Solution

$\begin{array}{l} I_{x} = 10^{- 3} (20 - 10 \cos 60^{\circ}) N - S = 15 \times 10^{- 3} N - S \\ = 15 \times 10^{- 3} N - S \\ I_{y} = 10^{- 3} \times 10 \sin 60^{\circ} N - S = 5 \sqrt{3} \times 10^{- 3} N - S \\ ∴ I = \sqrt{I_{x}^{2} + I_{y}^{2}} = \sqrt{3} \times 10^{- 2} N - S . \end{array}$

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