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# A bullet of mass m is fired into a block of wood of mass M which hangs on the end of pendulum andgets embedded into it. When the bullet strikes the wooden block, the pendulum starts to swing withmaximum rise R. Then, the velocity of the bullet is given by

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a
Mm+M2gR
b
M + mm2gR
c
Mm2gR
d
None of these

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detailed solution

Correct option is B

We know that,  v'=2gRFrom conservation of linear momentum,                        mv = (M+m)v'∴                       v=M+mm·v'=M+mm2gR

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