A bullet of mass m is fired into a block of wood of mass M which hangs on the end of pendulum andgets embedded into it. When the bullet strikes the wooden block, the pendulum starts to swing withmaximum rise R. Then, the velocity of the bullet is given by

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Mm+M2gR

M + mm2gR

Mm2gR

None of these

answer is B.

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Detailed Solution

We know that, v'=2gRFrom conservation of linear momentum, mv = (M+m)v'∴ v=M+mm·v'=M+mm2gR

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