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Questions  

A bullet of mass m moving with velocity v0 hits a wooden plank A of mass M placed on a smooth horizontal surface. The length of the plank is . The bullet experiences a
constant resistive force F inside the block. The minimum value of v0 such that it is able to come out of the plank is 

a
Fℓ/mM2
b
2Fℓ(M+m)Mm
c
2FℓmM2
d
Fℓ(M+m)Mm

detailed solution

Correct option is B

From Newton's third law a force F acts on the block in forward direction. Acceleration of block a1=FM Retardation of bullet a2=FmRelative retardation of bulletar=a1+a2=F(M+m)Mm Applying v2=u2−2arℓ0=v02−2F(M+m)Mm⋅ℓTherefore, minimum value of v0 isor  v0=2Fℓ(M+m)Mm

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