Questions
A bullet of mass m moving with velocity v0 hits a wooden plank A of mass M placed on a smooth horizontal surface. The length of the plank is . The bullet experiences a
constant resistive force F inside the block. The minimum value of v0 such that it is able to come out of the plank is
detailed solution
Correct option is B
From Newton's third law a force F acts on the block in forward direction. Acceleration of block a1=FM Retardation of bullet a2=FmRelative retardation of bulletar=a1+a2=F(M+m)Mm Applying v2=u2−2arℓ0=v02−2F(M+m)Mm⋅ℓTherefore, minimum value of v0 isor v0=2Fℓ(M+m)MmTalk to our academic expert!
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A block of mass kg rests on a horizontal frictionless xy-plane. What would be the acceleration of the block if it is subjected to two forces as shown in figure?
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