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A bullet of mass m moving with velocity v strikes a block of mass Mat rest and gets embedded into it. The kinetic energy of the composite block will be

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By Expert Faculty of Sri Chaitanya
a
12mv2mm+M
b
12mv2Mm+M
c
12mv2M+mm
d
12mv2M+mM

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detailed solution

Correct option is A

According to law of consecrations of momentummv=(m+M)v′  where v′= velocity of composite block  ∴ V′=mM+mV  K.E. of composite block =12(M+m)v′2 ∴  K.E. =12(M+m)mM+m2v2 =12mv2mM+m


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