A bullet of mass m moving with velocity v strikes a block of mass M at rest and gets embedded into it. The kinetic energy of the composite block will be

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12mv2×m(m+M)

12mv2×M(m+M)

12mv2×(M+m)M

12Mv2×m(m+M)

answer is A.

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Detailed Solution

By conservation of momentum, mv+M×0=(m+M)VVelocity of composite block V=mm+M vK.E. of composite block =12(M+m)V2=12(M+m) mM+m2v2=12mv2mm+M

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