Question

A bullet weighing 50 g leaves the muzzle of the gun with a velocity of 30 m/s. If the recoil speed imparted to the gun is 1 m/s, the mass of the gun:

Moderate

Solution

Velocity of the bullet relative to the ground =( 30-1) m/s = 29 m/s
Conserving momentum , m $\times 1 = \frac{50}{1000} \times 29 \Rightarrow M = 1.45 k g$

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