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A bullet when fired at a target with velocity of 100 ms-1 penetrates 1 m into it. If the bullet is fired at a similar target with a thickness 0.5 m, then it will emerge from it with a velocity of

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a
502m/s
b
502m/s
c
50m/s
d
10m/s

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detailed solution

Correct option is A

Let a be the deceleration of the bullet in both cases .Then  1002 = 2a×1 ...............1In the second case v2 =1002 - 2a×0.5 ..............2  Solving , v = 502 m/s


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