A bus travels distance $$x1$$ when accelerates from rest at constant rate $$a1$$ for some time and after that travels a distance $$x2$$ when decelerates at a constant rate $$a2$$ to come to $$x1+x2=a1a2t22a1+a2$$. Choose the correct $$option(s)$$.

Correct option is 1The relation is dimensionally correct

Questions

A bus travels distance x₁ when accelerates from rest at constant rate a₁ for some time and after that travels a distance x₂ when decelerates at a constant rate a₂ to come to $x_{1} + x_{2} = \frac{a_{1} a_{2} t^{2}}{2 (a_{1} + a_{2})} .$ Choose the correct option(s).

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The relation is dimensionally correct

The relation is dimensionally incorrect

The relation may be dimensionally correct

None of the above

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detailed solution

Correct option is A

LHS =x1+x2=x1=x2=M0LT0RHS=a1a2t22a1+a2 =LT−2LT−2T2LT−2=M0LT0∵ LHS = RHS According to homogeneity principle, equation is dimensionallycorrect.Hence, option (a) is correct.

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A bus travels distance x1 when accelerates from rest at constant rate a1 for some time and after that travels a distance x2 when decelerates at a constant rate a2 to come to x1+x2=a1a2t22a1+a2. Choose the correct option(s).

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A bus travels distance x₁ when accelerates from rest at constant rate a₁ for some time and after that travels a distance x₂ when decelerates at a constant rate a₂ to come to $x_{1} + x_{2} = \frac{a_{1} a_{2} t^{2}}{2 (a_{1} + a_{2})} .$ Choose the correct option(s).