By inserting a capillary tube upto a depth l in water, a capillary rise h is observed in the tube. If the lower end of the capillary tube is closed inside water and the capillary is taken out and closed end opened , to what height the water will remain in the tube when l > h
Let the length of water column in the tube be 'x'. F = surface tension force = 2πr.S; W = weight of water column = πx.ρ.g; h = capillary rise = 2s/ρrg
Now W = 2F ⇒ πxρg = 2 x 2πrS ⇒ x = 4s/ρrg = 2h