First slide

Electrostatic force

Question

$+ 2 C$ and $+ 6 C$ two charges are repelling each other with a force of 12N. If each charge is given $- 2 C$ of charge, then the value of the force will be

Easy

A

4 N (Attractive)
B

4 N (Repulsive)
C

8 N (Repulsive)
D

Zero

Solution

Resultant charges after adding the – 2C be $(- 2 + 2) = 0$ and
$(- 2 + 6) = + 4 C \Rightarrow F = \frac{k Q_{1} Q_{2}}{r^{2}} = k \times \frac{0 \times 4}{r^{2}} = 0$

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