In an A.C. circuit V and I are given byV=100sin(1000t) volt and I=1000sin(1000t+π/3)mAThe power dissipated in the circuit is
104 W
25 W
10 W
250 W
Power dissipated=Vr.m.s.×Ir.m.s.×cosϕP=V02×I02×cosϕ=1002×1000×10−32cosπ3=25W