In an A.C. circuit V and I are given byV=100sin⁡(1000t) volt and I=1000sin⁡(1000t+π/3)mAThe power dissipated in the circuit is

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104 W

25 W

10 W

250 W

answer is B.

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Detailed Solution

Power dissipated=Vr.m.s.×Ir.m.s.×cos⁡ϕP=V02×I02×cos⁡ϕ=1002×1000×10−32cos⁡π3=25W

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