At 27°C two moles of an ideal gas (γ=3/2) occupy a volume V. The gas expands adiabatically to a volume 2V. Final temperature of the gas approximately is

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189 K

212 K

248 K

179 K

answer is B.

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Detailed Solution

Here V1=V,V2=2V,T1=300KAdiabatic relation TV γ−1= constant T1V1γ−1=T2V2γ−1T2=T1V1V2γ−1=300121/2T2=212K.

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