Calculate the acceleration of the block and trolly system shown in the figure. The coefficient of kinetic friction between the trolly and the surface is $$0.05$$. (g$$ $$=$$ $$10$$ $$m/s2$$, mass of the string is negligible and no other friction $$exists).

Question

Calculate the acceleration of the block and trolly system shown in the figure. The coefficient of kinetic friction between the trolly and the surface is $$0.05$$. (g$$ $$=$$ $$10$$ $$m/s2$$, mass of the string is negligible and no other friction $$exists).

Infinity Learn · Accepted Answer

F. B. D. of trolly T−$$f=mTaf=$$μ$$mTgf=0.05$$×$$10$$×$$10f=5NT-5=10a$$      .....$$(i)F$$.B.D of blockmbg−$$T=mba2$$×$$10$$−$$T=2a20-T=2a$$   ......$$(ii)Equation$$ $$(i)+$$ $$(ii)15=12aa=1512$$⇒$$a=1.25m/s2$$

Calculate the acceleration of the block and trolly system shown in the figure. The coefficient of kinetic friction between the trolly and the surface is 0.05. ( $g = 10 m / s^{2}$ , mass of the string is negligible and no other friction exists).

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Calculate the acceleration of the block and trolly system shown in the figure. The coefficient of kinetic friction between the trolly and the surface is 0.05. (g = 10 m/s2, mass of the string is negligible and no other friction exists).

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Calculate the acceleration of the block and trolly system shown in the figure. The coefficient of kinetic friction between the trolly and the surface is 0.05. ( $g = 10 m / s^{2}$ , mass of the string is negligible and no other friction exists).