Calculate the amount of energy released on discharging a capacitor which has a potential difference of 200 V across its plates and 0.1 C charge is stored in it.
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
5 J
b
10 J
c
20 J
d
2.5 J
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Here, V = 200, q = 0.1 C.Energy stored,U=12qV=12×0.1×200=10JWhen the capacitor is discharged, it releases the same amount of energy i.e., 10 J.