Questions
Calculate the equivalent resistance of series combination of two resistors of resistances R1 =(300 ± 3) Ω and R1 = (500 ± 4) Ω respectively.
a
(800±1)Ω
b
(800±7)Ω
c
(200±7)Ω
d
(200±1)Ω
detailed solution
Correct option is B
The equivalent resistance of series combination isRs=R1+R2=300Ω+500Ωl=800ΩThe error in equivalent resistance is given byΔR=ΔR1+ΔR2=(3+4)Ω=7ΩHence, the equivalent resistance along with error is (800 ± 7)ΩTalk to our academic expert!
Similar Questions
Three 2 ohm resistors are connected to form a triangle. The resistance between any two corner is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
Popular Books
HC Verma Part 1HC Verma Part 2RS AgarwalRD SharmaLakhmir SinghDK GoelSandeep GargTS GrewalNCERT solutions
Class 12 NCERT SolutionsClass 11 NCERT SolutionsClass 10 NCERT SolutionsClass 9 NCERT SolutionsClass 8 NCERT SolutionsClass 7 NCERT SolutionsClass 6 NCERT Solutions
