Calculate the equivalent resistance of series combination of two resistors of resistances R1 =(300 ± 3) Ω and R1 = (500 ± 4) Ω respectively.

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

(800±1)Ω

(800±7)Ω

(200±7)Ω

(200±1)Ω

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The equivalent resistance of series combination isRs=R1+R2=300Ω+500Ωl=800ΩThe error in equivalent resistance is given byΔR=ΔR1+ΔR2=(3+4)Ω=7ΩHence, the equivalent resistance along with error is (800 ± 7)Ω

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET