Calculate the equivalent resistance of series combination of two resistors of resistances R1 =(300 ± 3) Ω and R1 = (500 ± 4) Ω respectively.

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(800±1)Ω

(800±7)Ω

(200±7)Ω

(200±1)Ω

answer is B.

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Detailed Solution

The equivalent resistance of series combination isRs=R1+R2=300Ω+500Ωl=800ΩThe error in equivalent resistance is given byΔR=ΔR1+ΔR2=(3+4)Ω=7ΩHence, the equivalent resistance along with error is (800 ± 7)Ω

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