Calculate the ground state Q value of the induced fission reaction in the equation
n+92U23→Zr4099+Te52134+3n
m(n)=1.0087u; MU235=235.0439u
M(Zr)=98.916u;MTe134=133.9115u
184.84 MeV
200 MeV
130 MeV
300 MeV
Q=Δm×931
[(235.0439+1.0087) −(98.916+133.9115+3.0261)×931]
Q=184.84MeV