First slide
Energy released in nuclear reactions -Q-value
Question

Calculate the ground state Q value of the induced fission reaction in the equation

n+92U23Zr4099+Te52134+3n

m(n)=1.0087u; MU235=235.0439u

M(Zr)=98.916u;MTe134=133.9115u

Moderate
Solution

Q=Δm×931

[(235.0439+1.0087) (98.916+133.9115+3.0261)×931]

Q=184.84MeV

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