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Calorimetry

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By Expert Faculty of Sri Chaitanya
Question

Calculate the heat of fusion of ice from the following data for ice at 0ºC added to water. Mass of calorimeter = 60 g, mass of calorimeter + water = 460 g, mass of calorimeter + water + ice = 618 g, initial temperature of water = 38°C, temperature of the mixture = 5°C. The specific heat of calorimeter = 0.10 ca lg-1 °C-1.

Moderate
Solution

Mass of water = 460 -60 = 400 g
Mass of ice = 618 - 460 =158 g
Heat lost by water = Heat gained by ice to melt +
Heat gained by (water + calorimeter) to reach 5ºC
Þ 400×1×(38-5) =158×L+158×1×5 + 60×0.1×5
(where L is the latent heat of fusion of ice)
 L = 78.35 calg–1


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