Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Calculate the magnetic moment (in Am2 ) of a thin wire with a current I=8 A, wound tightlly on a half a tore (see figure). The diameter of the cross section of the tore is equal to d=5 cm, and the number of turns is N=500.

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

answer is 5.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

The magnetic moment of circular current is given by Al, being the circulating current and A rs the area of cross-section; the direction is perpendicular to the plane of current. Now, for an element of toroid of length rdq, its magnetic moment is along the direction of arrow as shown, of magnitude (perpendicular to its cross-section) = current x area x number of turns in the length rdq.dM=Iπd24Nπrrdθ=N4d2IdθResolving dM into components along x and !, we get dM sin θ and dM cos θ; components along y from neighbouring elements cancel out to zero, and components along x are added. SoM=∫dMsinθ=∫0πN4·d2Isinθdθ=Nd2I2Putting the given values we get M = 5 Am2
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
Calculate the magnetic moment (in Am2 ) of a thin wire with a current I=8 A, wound tightlly on a half a tore (see figure). The diameter of the cross section of the tore is equal to d=5 cm, and the number of turns is N=500.