First slide

Law of equipartition of energy

Question

Calculate the number of degrees of freedom of molecules of Hydrogen in 1 cm³ of Hydrogen gas at NTP,

Moderate

A

2.34 × 10²⁰
B

3.34 × 10²⁰
C

1.34 × 10²⁰
D

4.34 × 10²⁰

Solution

Use $\large PV\, = \,nRT\, \Rightarrow \,n\, = \,\frac{{1.013 \times {{10}^5} \times {{10}^{ - 6}}}}{{8.3 \times 273}}$
Total number of degrees of freedom = $\large n \times {N_A} \times 5$
$\large = \,\frac{{1.013 \times {{10}^{ - 1}}}}{{8.3 \times 273}} \times 6.023 \times {10^{23}} \times 5\, = \,1.34 \times {10^{20}}$

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