Questions
Calculate percentage error in determination a time period of a pendulum
where, l and g are measured with ± 2% and ± 3% errors.
detailed solution
Correct option is B
ΔTT×100=±12×Δll×100+12×Δgg×100=±12×2+12×3=±2.5%Talk to our academic expert!
Similar Questions
The density of a cube is measured by measuring its mass and length of its sides. If the maximum errors in the measurement of mass and length are 3% and 2% respectively, then the maximum error in the measurement of density is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
