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Calculate percentage error in determination a time period of a pendulum 

T=2πlg  or  2π(lg)1/2

where, l and g are measured with ±2%  and  ±3%  errors.

a
2.9%
b
±2.5%
c
1.5%
d
±1.9%

detailed solution

Correct option is B

ΔTT×100=±(12×Δll×100+12×Δgg×100)=±(12×2+12×3)=±2.5%

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