Calculate the pressure inside a small air bubble of radius r situated at a depth of h below the free surface of liquids of densities ρ1 and ρ2 and surface tensions T1 and T2. The thickness of first and second liquids are h1 and h2. Take atmosphere pressure = P0.
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a
P0+ρ1gh1+ρ2g(h-h1)-2T2r
b
P0+ρ1gh1+ρ2g(h-h1)+2T2r
c
P0+ρ1g(h-h1)+2T2r
d
P0+ρ1gh2+ρ2g(h-h1)+2T2r
answer is B.
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Detailed Solution
PC = PB+2Tr PB =PA+ρ1gh1+ρ2g(h-h1)where PA = P0 PC = P0+ρ1gh1+ρ2g(h-h1)+2T2rThen evaluate by putting the numerical values.