Calculate the ratio of KE of molecule of oxygen and neon gas at 27° C
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a
53
b
35
c
43
d
34
answer is A.
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Detailed Solution
For oxygen gas number of degree of freedom is 5(KE)oxygen =52kT k is boltzmann constant;T is absolute temperatureNeon is mono atomic, therefore it has ‘3’ degree of freedom (KE)neon =32KT(KE)oxygen (KE)neon =52KT32KT=53