Calculate the ratio of the mean free paths of the molecules of two gases having molecular diameters 1A0 and 2A0. The gases may be considered under identical conditions of temperature, pressure and volume.
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a
1:4
b
4:1
c
1:2
d
2:1
answer is B.
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Detailed Solution
mean free path=λ=12πnd2 ;⇒ λ1α1d12 and λ1α1d12here n= number of collisions ;d=diameter of molecule; given d1=1A0 and d2=2A0⇒λ1λ2=d2d12=212=41