Calculate the temperature at which the oxygen molecules will have the same rms velocity as the hydrogen molecules at 150° C. Molecular weight of oxygen is 32 and that of hydrogen is 2.
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
6495° C
b
7000° C
c
7495° C
d
8000° C
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
root mean square velocity =Vrms=3RTM ;here R is universal gas constant;T is absolute temperature; M is molecular weight of gas given root mean square velocity are equal; V1=V2 and T1=150+273=423; T2=? M1=2; M2=32; Therefore T∝M T1T2=M1M2substitute the given values,T2=T1M2M1=423322T2=6768Kt2=6768−273=6495∘C