A calorimeter contains $$0.2$$ kg of water at $$30$$°C. $$0.1$$ kg of water at $$60$$°C is added to it, the mixture is well stirred and the resulting temperature is found to be $$35$$°C. The thermal capacity of the calorimeter is

Question

Infinity Learn · Accepted Answer

Let X be the thermal capacity of calorimeter and spe­cific heat of water $$=$$ $$4200$$ $$J/kg-K$$.Heat lost by $$0.1$$ kg of water $$=$$ Heat gained by water in calorimeter $$+$$ Heat gained by $$calorimeter0.1$$ × $$4200$$ × (60$$ $$-$$ $$35) $$=$$ $$0.2$$ × $$4200$$ × (35$$ $$-$$ $$30) $$+$$ $$X(35$$ $$-$$ $$30)$$                         $$10500$$ $$=$$ $$4200$$ $$+$$ $$5X$$ ⇒ X $$=$$ $$1260$$ $$J/K$$

A calorimeter contains 0.2 kg of water at 30°C. 0.1 kg of water at 60°C is added to it, the mixture is well stirred and the resulting temperature is found to be 35°C. The thermal capacity of the calorimeter is

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