A calorimeter of mass 0.2 kg and specific heat 900 J/kg/K. Containing 0.5 kg of a liquid of specific heat 2400J/kg/K. Its temperature falls from 600C to 550C in one minute. Find the rate of cooling.
5 J/s
15 J/s
100 J/s
115 J/s
Rate of cooling (here it is rate of loss of heat)
dQdt= (mc+W)dQdt = (m1c1+mccc)dθdt
⇒ dQdt = (0.5×2400+0.2×900)(60-5560)
= 115 J/sec