Q.

A calorimeter of water equivalent 20 g contains 180g of water at 250C. ‘m’ grams of steam at 1000C is mixed in it till the temperature of the mixture is 310C. The value of ‘m’ is close to (Latent heat of water = 540 cal g-1, specific heat of water = 1 cal g-1   0C-1)

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

2

b

4

c

3.2

d

2.6

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Heat gained by cold body = heat lost by hot body⇒20+180×1×31-25=m(540)+m×1×100-31⇒1200=m(609)⇒m≈2gms
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
whats app icon
A calorimeter of water equivalent 20 g contains 180g of water at 250C. ‘m’ grams of steam at 1000C is mixed in it till the temperature of the mixture is 310C. The value of ‘m’ is close to (Latent heat of water = 540 cal g-1, specific heat of water = 1 cal g-1   0C-1)