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Questions  

A Camot engine having an efficiency of 110 as heat engine, is used as a refrigerator. If the work done on the system is l0 J, the amount of energy absorbed from the reservoir at lower temperature is:

a
90 J
b
99 J
c
100 J
d
1 J

detailed solution

Correct option is A

Efficiency = Wq1 = 10q1 = 110  ⇒ q1 = 100 J⇒q2 = q1-W = 100-10 = 90 J

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